Question

A gas balloon has a volume of 80.0 mL at 300K, and a pressure of 50.0 kPa. If the pressure changes to 80 kPa and the temperature rises to 320K, what is the new volume of the balloon in millimeters?

Answer 1

Answer: The new volume is 53.3 ml

Step-by-step explanation:

The combined gas equation is,

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

where,

`P_1` = initial pressure of gas = 50.0 kPa

`P_2` = final pressure of gas = 80.0 kPa

`V_1` = initial volume of gas = 80.0 ml

`V_2` = final volume of gas = ?

`T_1` = initial temperature of gas =
`300K`

`T_2` = final temperature of gas =
`320K`

Now put all the given values in the above equation, we get:

`(50.0* 80.0)/(300)=(80.0* V_2)/(320)`

`V_2=53.3ml`

The new volume is 53.3 ml