Question

I need help bad bro i have a 30 cs this is missing

Answer 1

Answer: 11.02 moles of Ag can be formed.

Step-by-step explanation:

To calculate the moles :

`\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}`

`\text{Moles of} Cu=(350.00g)/(63.55g/mol)=5.51moles`

The balanced chemical equation is:

`Cu+2AgNO_3\rightarrow Cu(NO_3)_2+2Ag`

According to stoichiometry :

1 moles of
`Cu` produces = 2 moles of
`Ag`

Thus 5.51 moles of
`Cu` will produce=
`(2)/(1)* 5.51=11.02moles` of
`Ag`

Thus 11.02 moles of Ag can be formed.