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Find the minimum value of the parabolay = x^(2) + 3x + 2
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Find the minimum value of the parabola
y = x^(2) + 3x + 2

User Michael Rush
by
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1 Answer

2 votes
Y=2
X= -3/2
Vertex= -3/2 and -1/4
User Mikulas Dite
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