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Which equation is y = (x + 3)2 + (x + 4)2 rewritten in vertex form? y = 2 (x + seven-halves) squared minus one-fourth y = 2 (x + seven-halves) squared minus one-half y = 2(x + 7)2 – 73 y = (x + 7)2 – 24
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Which equation is y = (x + 3)2 + (x + 4)2 rewritten in vertex form?

y = 2 (x + seven-halves) squared minus one-fourth
y = 2 (x + seven-halves) squared minus one-half
y = 2(x + 7)2 – 73
y = (x + 7)2 – 24

User Aniket Thakur
by
8.4k points

1 Answer

6 votes

Answer:

The person above is correct B)y=2(x+7/2)²+1/2

Explanation:

User Kelsier
by
8.1k points
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