Question

A 5.0-g sample of Substance X increases in temperature from 20.0°C to 22.0°C when it absorbs 9.6J of heat. What is the specific heat of

Substance X in J/g °C)?

Answer 1

0.96 J/g °C

General Formulas and Concepts:

Thermochemistry

Specific Heat Formula: q = mcΔT

• m is mass (in grams)
• c is specific heat (in J/g °C)
• ΔT is change in temperature, final - initial (in °C)

Step-by-step explanation:

Step 1: Define

[Given] m = 5.0 g

[Given] ΔT = 22.0 °C - 20.0 °C = 2.0 °C

[Given] q = 9.6 J

[Solve] c

Step 2: Solve for c

1. Substitute in variables [Specific Heat Formula]: 9.6 J = (5.0 g)c(2.0 °C)
2. [Specific Heat] Multiply: 9.6 J = (10. g °C)c
3. [Specific Heat] Isolate c: 0.96 J/g °C = c
4. [Specific Heat] Rewrite: c = 0.96 J/g °C