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At standard temperature and pressure. 0.500 mole of xenon gas occupies

User Absence
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1 Answer

14 votes
14 votes

Answer:

0.500 mole of Xe (g) occupies 11.2 L at STP.

General Formulas and Concepts:

Gas Laws

  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

Stoichiometry

  • Mole ratio
  • Dimensional Analysis

Step-by-step explanation:

Step 1: Define

Identify.

0.500 mole Xe (g)

Step 2: Convert

  1. [DA] Set up:
    \displaystyle 0.500 \ \text{mole Xe} \bigg( \frac{22.4 \ \text{L Xe}}{1 \ \text{mole Xe}} \bigg)
  2. [DA] Evaluate:
    \displaystyle 0.500 \ \text{mole Xe} \bigg( \frac{22.4 \ \text{L Xe}}{1 \ \text{mole Xe}} \bigg) = 11.2 \ \text{L Xe}

Topic: AP Chemistry

Unit: Stoichiometry

User Karl Knechtel
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