Answer:
pH = 10
Step-by-step explanation:
KOH is a strong base; thus it will completely dissociate:
KOH -> K⁺ + OH⁻
Since it completely dissociates, the concentration of both K⁺ and OH⁻ will be the concentration of KOH given (1.0 x 10^-4 M).
We can then find pOH by taking the negative log of the OH⁻, or hydroxide, concentration:
pOH = -log[OH⁻] = -log[1.0 x 10^-4 M] = 4
At 25 degrees Celsius, pH + pOH = 14. If we solve for pH and then plug in our pOH, we get:
pH = 14 - pOH = 14 - 4 = 10
The pH of a 1.0 x 10^-4 M solution of KOH is thus 10.