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(m+2)^2=27 solve by square root property when i did it i got: m=±√27-4 is that correct?

(m+2)^2=27 solve by square root property when i did it i got: m=±√27-4 is that correct?
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(m+2)^2=27

solve by square root property

when i did it i got: m=±√27-4
is that correct?

User Frederik Winkelsdorf
by
8.4k points

1 Answer

0 votes

Answer:

Yes, that's correct

Explanation:

User Pasindu Jayanath
by
8.2k points
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