Question

NEED ANSWER ASAP -50 POINTS

Answer 1

`x+(3)/(x)=7`

This is a disguised quadratic equation. To solve it, we must first multiply each term by x to get rid of the fraction:

`x* x+(3)/(x) * x=7 * x`

`x^2+3=7x`

Now, we could solve this equation like a normal quadratic. Move all terms to the left side of the equation:

`x^2-7x+3=0`

To solve for x, we could use the quadratic formula:

`x=(-b \pm √(b^2-4ac))/(2a)` where the given equation is
`ax^2+bx+c=0`

Given
`x^2-7x+3=0`, we know that:

a = 1

b = -7

c = 3

Plug in a, b and c:

`x=(-(-7) \pm √((-7)^2-4(1)(3)))/(2(1))\\\\x=(7 \pm √(49-12))/(2)\\\\x=(7 \pm √(37))/(2)`

Therefore, the two solutions for x are
`x=(7 - √(37))/(2)` and
`x=(7 + √(37))/(2)`.

I hope this helps!