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Question

asked May 19, 2023 192k views

1 Answer

Larp · Answer 1 · 2023-05-24T13:11:33+0000

The quadratic formula can help us solve for x in a quadratic equation:

$x=(-b \pm √(b^2-4ac))/(2a)$

We can use this when the given equation is organized in standard form:
ax^2+bx+c=0

2x^2+5x-4=0

First we can identify the values of a, b and c:

a = 2

b = 5

c = -4

Plug these values into the quadratic formula:

$x=(-b \pm √(b^2-4ac))/(2a)$

$x=(-5 \pm √(5^2-4(2)(-4)))/(2(2))$

$x=(-5 \pm √(25+32))/(4)$

$x=(-5 \pm √(57))/(4)$

Therefore, the two possible values of x are:

x=(-5 +√(57))/(4)

x=(-5 -√(57))/(4)