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Differentiate with respect to x:y= sinh^-1(x^2+1)

User Ravi Wadje
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1 Answer

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Answer:

The first derivative of
y = \sinh^(-1) (x^(2)+1) is
y' = \frac{2\cdot x}{\sqrt{x^(2)+2\cdot x +2}}.

Explanation:

We proceed to find the first derivative of
y = \sinh^(-1) (x^(2)+1) by explicit differentiation and rule of chain:


y = \sinh^(-1) (x^(2)+1)


y' = \frac{2\cdot x}{\sqrt{(x^(2)+1)^(2)+1}}


y' = \frac{2\cdot x}{\sqrt{x^(2)+2\cdot x +2}}

The first derivative of
y = \sinh^(-1) (x^(2)+1) is
y' = \frac{2\cdot x}{\sqrt{x^(2)+2\cdot x +2}}.

User JRI
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