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Does anyone know how to do any of these types of problems?

Does anyone know how to do any of these types of problems?-example-1
User BGStack
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1 Answer

3 votes

9514 1404 393

Answer:

150°

Explanation:

The rule here is that the external angle is half the difference of the arcs subtended. That relation is used to form an equation, which can then be solved for whatever measure is of interest.

(RB -EC)/2 = D

((13x +7) -(60))/2 = (5x -10)

13x -53 = 10x -20 . . . . . . . . . . multiply by 2

3x = 33 . . . . . . . . . . . . . . add 53-10x to both sides

x = 11 . . . . . . . . . . . . divide by 3

RB = 13x +7 = 13·11 +7 = 150

The measure of arc RB is 150°.

User Ncraley
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4.0k points