Answer:
3-methyl-2-butanone.
Step-by-step explanation:
Hello there!
In this case, for these types of oxidation of secondary alcohols, due to the 2-butanol, it is possible for us to remember that the product is a ketone exhibiting a carbonyl (C=O) group as the product of the oxidation. In such a way, the reaction would be:
CH3 - CH - CH - CH3 -------> CH3 - C - CH - CH3
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OH CH3 O CH3
Therefore, the product would be 3-methyl-2-butanone.
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