Question

The pressure of an ideal gas stays constant at 2.57 atm.

This ideal gas has a volume of 45.8 mL when it is at a
temperature of 37.0°C. What temperature will this ideal gas
be at when it contracts to 32.5 mL?

Answer 1

`T_2=-53.15\°C`

Step-by-step explanation:

Hello there!

In this case, in agreement to the Charles' law which states that the volume and temperature relate to each other via a directly proportional relationship at constant pressure, we can write:

`(T_2)/(V_2) =(T_1)/(V_1)`

Thus, given V1, V2 and T1 (310 in Kelvin), we can solve for the final temperature as shown below:

`T_2=(T_1V_2)/(V_1) \\\\T_2=(310K*32.5mL)/(45.8mL)\\\\T_2=220 K-273.15K\\\\T_2=-53.15\°C`

Best regards!