Answer:
Combine multiplied terms into a single fraction
13(−6+4)=−112(4+4)
13(−6q+4)=−112(4q+4)\frac{1}{3}(-6q+4)=\frac{-1}{12}(4q+4)31(−6q+4)=12−1(4q+4)
1(−6+4)3=−112(4+4)
1(−6q+4)3=−112(4q+4)\frac{1(-6q+4)}{3}=\frac{-1}{12}(4q+4)31(−6q+4)=12−1(4q+4)
2
Multiply by 1
3
Combine multiplied terms into a single fraction
4
Distribute
5
Multiply all terms by the same value to eliminate fraction denominators
6
Cancel multiplied terms that are in the denominator
7
Distribute
8
Subtract
16
161616
from both sides of the equation
9
Simplify
10
Add
4
4q4q4q
to both sides of the equation
11
Simplify
12
Divide both sides of the equation by the same term
13
Simplify
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Solution
=1
Explanation: