Question

M&M plain candies have a normally distributed weight with a mean of 0.8565 g and a standard

deviation of 0.0518 g. If 465 M&M plain candies are randomly selected, find the probability that

their mean weight is at least 0.8535 g each.

Answer 1

0.89417

Explanation:

Using the relation to obtain the Zscore :

Z = (x - mean) ÷ standard deviation / sqrt(n)

x = 0.8535

Mean = 0.8565

Standard deviation = 0.0518

Sample size, n = 465

P(x ≤ 0.8535) = (0.8535 - 0.8565) ÷ 0.0518/sqrt(465)

P(x ≥ 0.8535) = - 0.003 / 0.0024021

P(x ≥ 0.8535) = - 1.249

P(Z ≥ - 1.249) = 0.89417