Answer:
442 Hz, 882 Hz, 1330 Hz
Step-by-step explanation:
Given data: length of the string= 0.31 m = 31 cm
speed of the waves = 274.4 M/s or 2740 cm/s
Wavelengths are
62 cm
31 cm and
62 / 3 = 20.67 cm
The frequencies associated with these wavelengths ( which are the 1st, 2nd and 3rd harmonics )
are
27440/ 62 = 442.6 = 442 Hz
27440/31 = 885.2 = 882 Hz
27440 / 20.67 = 1328 = 1330 Hz