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The amount of energy required to heat 0.5 kilograms of water until the temperature increases 12° C is about

1 Answer

5 votes

Answer:

Q = 25104 / 4.184 = 6000 Calories or 6 Kcal

Step-by-step explanation

Energy can be calculated by the equation

Q = m x Cp x delta T

where

m = mass = 0.5 kg

Cp = specific heat of water = 4184 J

Delta T = 12 degrees

Multiplying all

Q = 0.5 x 4184 x 12 = 25104 Joules

Converting it to Calories

Q = 25104 / 4.184 = 6000 Calories or 6 Kcal

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