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Oil leaks out of a tanker at a rate of r=f(t) liters per minute, where t is in minutes. If f(t)=Ae^(−kt), write a definite integral expressing the total quantity of oil which leaks out of the tanker in the first hour.

User Johan D
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Answer:

The definite integral expressing the total quantity of oil, 'V', which leaks out of the tanker in the first hour is given as follows;


V = \int\limits^(60)_0 {A \cdot e^((-k \cdot t))} \, dt

Explanation:

From the question, we have;

The rate at which oil leaks out of the tanker, r = f(t)

The unit of the oil leak = Liters per minute

The unit of t = Minutes


If \ f(t) = A \cdot e^((-k \cdot t ))

Therefore, we have;

The definite integral expressing the total quantity, 'V', of oil which leaks out of the tanker in the first hour is given as follows;


V = \int\limits^(60)_0 {A \cdot e^((-k \cdot t))} \, dt

Therefore, we have;


\int\limits^(60)_0 {A \cdot e^((-k \cdot t))} \, dt = (A \cdot e ^(60 \cdot k) - A)/(k \cdot e ^(60 \cdot k) )

User Prince Agrawal
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