Question

2. Given log35 = 1.465, approximate the value of log325.

Answer 1

9514 1404 393

Answer:

2.930

Explanation:

The applicable rule of logarithms is ...

log(a^b) = b·log(a)

___

Here, this means ...

`\log_3(25)=\log_3(5^2)=2\cdot\log_3(5)=2\cdot1.465\\\\\boxed{\log_3(25)=2.930}`