Question

ABCD is a square with an area of 49 cm2, and BE = 4.95 cm. Point E is the midpoint of 2 diagonal lines crossed inside the square.

Answer 1

I suppose we want to find the side length of the square.

We know that:

The area of the square is 49cm^2

The distance between one of the vertices of the square and the middle of the square is:

BE = 4.95cm

Now let's remember some things.

For a square of side length L, the area is:

A = L^2

and the diagonal length is:

D = √(2)*L

In this case, we know that half of the diagonal is equal to:

BE = 4.95 cm

Then the diagonal is:

D = 2*BE = 2*4.95cm = 9.9cm

And for the diagonal formula, we have:

D = 9.9cm = √(2)*L

Then the side length is:

L = 9.9cm/√(2) = 7cm

And if we check the area of this square, is:

A = L^2 = (7cm)^2 = 49cm^2

So it checks.

Then we can conclude that the sidelength of the square is 7cm, which means that:

AB = 7cm

BC = 7cm

CD = 7cm

DA = 7cm