Factor completely: 4y^2 - y - 3

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asked Nov 18, 2023 111k views

13 votes

Factor completely: 4y^2 - y - 3

Computers and Technology
college

Jim Holden asked

by Jim Holden

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2 Answers

7 votes

Answer:

(y - 1)(4y + 3)

Step-by-step explanation:

$4 {y}^(2) - y - 3$

$4 {y}^(2) - 4y + 3y - 3$

4y(y - 1) + 3(y - 1)

(y - 1)(4y + 3)

Andreihondrari answered Nov 19, 2023

by Andreihondrari

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13 votes

Answer:

(4y + 3)(y - 1)

Step-by-step explanation:

$4 {y}^(2) - y - 3$

$4 {y}^(2) - 4y + 3y - 3$

4y(y - 1) + 3(y - 1)

(4y + 3)(y - 1)

Aleksander Monk answered Nov 22, 2023

by Aleksander Monk

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