Answer:
d = 493.72 m
Step-by-step explanation:
Given that,
Initial velocity of the train, u = 80 km/h = 22.22 m/s
Acceleration of the train, a = -0.5 m/s² (negative as it slows down)
Finally brakes are applied, v = 0
We need to find the distance the train travels. Let the distance be d. Using third equation of kinematics to find it.

So, the required distance is equal to 493.72 m.