Answer: 0.1974
Explanation:
Let X be a random variable that denotes the gas mileage (in miles per gallon) of the individual sedan.
Given: Population mean:

Standard deviation:

The probability that the gas mileage (in miles per gallon) of your single, individual sedan is between 19.5 and 20.5:
![P(19.5<x<20.5)=P((19.5-20)/(2)<(x-\mu)/(\sigma)<(20.5-20)/(2))\\\\=P(-0.25<z<0.25)=2P(0.25)-1 [P(-z<Z<z)=2P(Z<z)-1]\\\\=2(0.5987)-1=0.1974](https://img.qammunity.org/2022/formulas/mathematics/college/uxczqap4cc2prq8zk0jhncve6m79kvfoba.png)
The required probability=0.1974