Question

What is the electrical force between 91 and 92? Recall

that k = 8.99 * 109 Nom?
2 m
9, +6 C
9,=-40
+1 m +
O 4.3 x 1010 N
q = +3 C O 3,5 x 1010 N
O -5.4 x 1010 N
O -5.8 x 10101

Answer 1

C on edge

Edge2021

Answer 2

F = 5.39 x 10¹⁰ N

Step-by-step explanation:

The electrical force between q₁ and q₂ can be calculated by Coulomb's Law:

`F = (kq_1q_2)/(r^2)\\\\`

where,

F = electrical force = ?

k = Coulomb Constant = 8.99 x 10⁹ Nm²/C²

q₁ = first charge = +6 C = 6 C

q₂ = -4 C = 4 C

r = distance between charges = 2 m

Therefore,

`F = ((8.99\ x\ 10^9\ N.m^2/C^2)(6\ C)(4\ C))/((2\ m)^2)\\\\`

F = 5.39 x 10¹⁰ N