Answer:
the system will be worth $1892.25 after 2 years.
Step-by-step explanation:
as the value decreases:
......notice the ' - ' as its *decreases*
given:
- P = 2500
- n = 1 per year
- t = 2 years
- r = 13%
solve:
![\sf A = 2500(1 - (0.13)/(1))^(1*2)](https://img.qammunity.org/2023/formulas/mathematics/high-school/3tgptn65oxmpetw0r253s4ctiy8aljycj5.png)
![\sf A = 1892.25](https://img.qammunity.org/2023/formulas/mathematics/high-school/i7jf22u8l9kg9kujns522s3uqhvw1onu4f.png)
another way of doing it easily is:
[ $2500 * (100- 13)% ] * (100- 13)% = $1892.25