29.5k views
4 votes
F of x equals the integral from 0 to x of the cosine of t squared . Use your calculator to find f '(1).

1. 0.709
2. 0.292
3. 0.842
4. 0.540

User Kasean
by
8.1k points

1 Answer

7 votes

Answer:

First, if we have a function defined as:


G(x) = \int\limits^x_0 {f(t)} \, dt

then:

G'(x) = f(x)


F(x) = \int\limits^x_0 {cos(t)^2} \, dt

then:

F' = dF/dt = cos(t)^2

F'(1) = cos(1)^2 = 0.2919

If we round it up to the third digit after the decimal point we get:

F'(1) = 0.292

The correct option is the second one.

User JasonFruit
by
8.6k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories