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Tell how many solutions each one has

Tell how many solutions each one has-example-1

1 Answer

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Answer:

Explanation:

1) 3(x + 2 ) +4 = 31

3*x + 2*3 + 4 = 31

3x + 6 + 4 = 31

3x + 10 = 31 {Subtract 10 from both sides}

3x = 31 - 10

3x = 21 {divide both sides by 3}

x = 21/3

x = 7

This equation has one solution

2) 3x + 1 = 3x + 9

Subtract 3x form both sides

3x + 1 -3x = 3x + 9 - 3x

1 ≠ 9

There is no solution for this equation.

3) 2x - 4 = 2x -4

This equation has many solution

User Andrew Koper
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