Question

URGENT PLS I NEED THIS OR I WILL FAIL AND HAVE TO DO SUMMER SCHOOL

Carbon monoxide gas and oxygen gas combine to form carbon dioxide
gas in the following equation:
2CO(g) + O2(g) → 2CO2(g)
The enthalpy value for gaseous carbon monoxide is -110.5, and gaseous
carbon dioxide is -393.5, calculate the enthalpy change (AH) for the
reaction.

Answer 1

ΔHr = -566kJ/mol

Step-by-step explanation:

Based on Hess's law, the ΔH of a reaction is the sum of the ΔH's of products times its coefficient subtracting the ΔH of reactants. For the reaction:

2CO(g) + O2(g) → 2CO2(g)

ΔH is:

ΔHr = 2*ΔH CO2 - (2ΔH CO + ΔH O2)

As ΔH CO2 = -393.5kJ/mol; ΔH CO = -110.5kJ/mol and ΔH O2 = 0kJ/mol

ΔHr = 2*-393.5kJ/mol - (2*-110.5kJ/mol)

ΔHr = -566kJ/mol