Answer:
t = 22.22 s
Explanation:
Given that,
The initial speed of the train, u = 40 km/h
Acceleration of the train, a = 0.5 m/s²
Finally, it stops, v = 0
We need to find the time taken by it to stop. using first equation of motion to find it such that,
![v=u+at\\\\t=(v-u)/(a)\\\\t=(0-40* (5)/(18))/(-0.5)\\\\t=22.22\ s](https://img.qammunity.org/2022/formulas/mathematics/college/xbxodfj8qx2pd6hvhhrm8alirk86duigjo.png)
So, it will take 22.22 seconds to stop.