Question

Complete the following double displacement reactions

KOH + H 2 SO 4 
NaOH + HCl 
Al 2 (SO 4 ) 3 + NaOH 
BaCl 2 + Na 2 SO 4 
PbSO 4 + Na 2 CO 3 

Answer 1

2 KOH + H₂SO₄ ⇒ K₂SO₄ + 2 H₂O

NaOH + HCl ⇒ NaCl + H₂O

Al₂(SO₄)₃ + 6 NaOH ⇒ 3 Na₂SO₄ + 2 Al(OH)₃

BaCl₂ + Na₂SO₄ ⇒ BaSO₄ + 2 NaCl

PbSO₄ + Na₂CO₃ ⇒ PbCO₃ + Na₂SO₄

Step-by-step explanation:

In double displacement reactions, both reactants exchange their cations and anions.

2 KOH + H₂SO₄ ⇒ K₂SO₄ + 2 H₂O

NaOH + HCl ⇒ NaCl + H₂O

Al₂(SO₄)₃ + 6 NaOH ⇒ 3 Na₂SO₄ + 2 Al(OH)₃

BaCl₂ + Na₂SO₄ ⇒ BaSO₄ + 2 NaCl

PbSO₄ + Na₂CO₃ ⇒ PbCO₃ + Na₂SO₄