128k views
5 votes
1. What is the equation of a parabola that has a vertex at (-2, 4) and goes through the point (0,8)?

1 Answer

4 votes

Answer:

y - k = (x + 2)^2

Explanation:

The vertex equation of a vertical parabola is

y - k = a(x - h)^2, where (h, k) is the vertex.

We are given h = -2, k = 4, x = 0 and y = 8 and need to find the value of a.

8 - 4 = a(0 + 2)^2, or

4 = 4a, so a must be 1.

Then the desired equation is:

y - k = (x + 2)^2

User Elliot Coad
by
7.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories