Question

A train leaves Miami at 4:00 PM. A second train leaves the same city in the same direction at 8:00 PM. The second train travels 124mph faster than the first. If the second train overtakes the first at 10:00 PM, what is the speed of each of the two trains?

Answer 1

Distance travelled = speed x time
If we call the speed of the slower train S and the speed of the faster train F then
S x 6 hours = F x 2 = (S + 124) x 2
6S = 2S + 248
4S = 248
S = 62
So the slow train is travelling at 62mph and the fast train at 186mph