1. How many grams are in 1.4 moles of Mg(NO3)2?

asked Jun 17, 2022 160k views

1 vote

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Step-by-step explanation:

molar mass of the compound = 24 + 2× 14+ 16×6

= 24 + 28 + 96

= 148g/mol

no of moles = given mass / molar mass of the compound

1.4 = given mass/ 148

1.4×148=given mass

207.2 g

Kadir Ercetin answered Jun 22, 2022

4.2k points

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