Question

1. Find the length of the hypotenuse. (1 point)
45°
3V5
O 12
05
O 18

Answer 1

6

Explanation:

Using the sine ratio in the right triangle and the exact value

sin45° =
`(1)/(√(2) )` , then

sin45° =
`(opposite)/(hypotenuse)` =
`(3√(2) )/(h)` =
`(1)/(√(2) )` ( cross- multiply )

h = 3
`√(2)` ×
`√(2)` = 6

the hypotenuse is 6 units