What is the average rate of change of the function below on the interval [0, 0.5]? F(x)= x^2+7x+10/ x^2 - 7x+6 A. 8.333 B. 6.333 C. 7.666 D. 6.667

asked Jul 2, 2022 48.3k views

5 votes

What is the average rate of change of the function below on the interval [0, 0.5]?

F(x)= x^2+7x+10/ x^2 - 7x+6
A. 8.333
B. 6.333
C. 7.666
D. 6.667

by Hyori

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3 votes

Answer:

Explanation:

F(0)= 0^2+7(0)+10/ 0^2 - 7(0)+6 = 1.67

F(0.5)= 0.5^2+7(0.5)+10/ 0.5^2 - 7(0.5)+6 = 5

RateofChange = (F(0.5) - F(0))/(0.5 - 0) = 6.667

4.1k points

5 votes

Answer:

add all the numbers and divide by 4

Explanation:

Amflare answered Jul 6, 2022

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