Question

In ΔPQR, the measure of ∠R=90°, QR = 61 feet, and RP = 90 feet. Find the measure of ∠P to the nearest degree.

Answer 1

Explanation:

given= in triangle PQR,<R=90⁰ QR=61 FEET RP=90 FEET

by using pythagoras therom ;

(hypotenuse)²=(side1)² +(side2)²

(PQ)²=(PR)²+(QR)²

(PQ)²=(90)² + (61)²

(PQ)²=8100 + 3721

(PQ)²=11821

TAKING SQUARE ROOTS ON BOTH SIDES, WE GET;

PQ= 108 feet

<P = thita

sin ⁰ = opposite/hypotenuse

sin⁰ =QR/PQ

SIN⁰ =61/108

SIN⁰ =0.56

there amgle P measures 0.56 degree

Answer 2

34

Explanation:

its right