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1 vote
What is the equation of the line that passes through (4, 3) and (-4, -1)?

y = 2 x + 7
y = + 1
2 x + 1
y = + 7

User Soviero
by
6.8k points

1 Answer

4 votes

Answer:

Explanation:

First find the slope of the line

(4 , 3) ; x₁ = 4 ; y₁ = 3

(-4,-1) ; x₂ = -4 ; y₂ = -1

slope
= (y_(2)-y_(1))/(x_(2)-x_(1))\\\\


=(-1-3)/(-4-4)\\\\=(-4)/(-8)\\\\=(1)/(2)

m = 1/2 , and take any one point (4 , 3)

y -y1 = m(x - x1)


y - 3 = (1)/(2)(x - 4)\\\\y -3 = (1)/(2)x-4*(1)/(2)\\\\y - 3 =(1)/(2)x - 2\\\\y = (1)/(2)x - 2 + 3\\\\y =(1)/(2)x + 1

User TSR
by
6.9k points
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