Question

What is the equation of the line that passes through (4, 3) and (-4, -1)?

y = 2 x + 7
y = + 1
2 x + 1
y = + 7

Answer 1

Explanation:

First find the slope of the line

(4 , 3) ; x₁ = 4 ; y₁ = 3

(-4,-1) ; x₂ = -4 ; y₂ = -1

slope
`= (y_(2)-y_(1))/(x_(2)-x_(1))\\\\`

`=(-1-3)/(-4-4)\\\\=(-4)/(-8)\\\\=(1)/(2)`

m = 1/2 , and take any one point (4 , 3)

y -y1 = m(x - x1)

`y - 3 = (1)/(2)(x - 4)\\\\y -3 = (1)/(2)x-4*(1)/(2)\\\\y - 3 =(1)/(2)x - 2\\\\y = (1)/(2)x - 2 + 3\\\\y =(1)/(2)x + 1`