Question

How many grams is 2.393 x 10^24 atoms of CI

70.45 g CI
140.9 ga
140.9 mole CI
70.45 mole CI
How many grams is 2.393 x 10^24 atoms of O
70.45 g O
140.9 g O
63.58 mole O
63.58 g O

Answer 1

Answer: 1. 140.9 g Cl

2. 63.58 g O

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
`6.023* 10^(23)` of particles.

To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given atoms}}{\text {avogadro's number}}`

1.
`\text{Number of moles of Cl}==(2.393* 10^(24))/(6.023* 10^(23))=3.973moles`

1 mol of Cl weighs = 35.5 g

Thus 3.973 mol of Cl weighs =
`(35.5)/(1)* 3.973=140.9g`

2.
`\text{Number of moles of O}==(2.393* 10^(24))/(6.023* 10^(23))=3.973moles`

1 mol of O weighs = 16 g

Thus 3.973 mol of O weighs =
`(16)/(1)* 3.973=63.58g`