Question

A +0.0129 C charge feels a 4110 N

force from a -0.00707 C charge. How
far apart are they?
[?] m

Answer 1

14.13 m

Step-by-step explanation:

acellus

Answer 2

r = 14.13 m

Step-by-step explanation:

Given that,

Charge 1 = +0.0129 C

Charge 2 = -0.00707 C

The force between charges, F = 4110 N

We need to find the distance between charges. Let the distance be r. The force between two charges is given by :

`F=(kq_1q_2)/(r^2)\\\\4110=(9* 10^9* 0.0129* 0.00707)/(r^2)\\\\r=\sqrt{(9* 10^9* 0.0129* 0.00707)/(4110)} \\\\r=14.13\ m`

So, the distance between charges is equal to 14.13 m.