Question

Help me with this problem please

Answer 1

`(a)\ A_1 = s^2`

`(b)\ A_2 = 4s^2`

(c) 4 small squares

Explanation:

Given

Small Square:

`Dimension: s`

Large Square:

`Dimension: 2s` i.e. twice as long as the small square

Solving (a): The area of the small square.

This is calculated as

`Area = Length^2`

So, we have:

`A_1 = s^2`

Solving (b): The area of the large square.

This is calculated as

`Area = Length^2`

So, we have:

`A_2 = (2s)^2`

`A_2 = 4s^2`

Solving (c): Number of small square to cover the large square

To do this, we simply divide their areas.

Let n represents the required number; n is calculated as:

`n = (A_2)/(A_1)`

`n = (4s^2)/(s^2)`

`n = 4`

Hence, 4 small squares is required to cover the large square