Question

6 NaOH + 2 Al --> 2 Na3AlO3 + 3 H2 If you start with 258 g of Al, how many moles of Na3AlO3 can you make?

Answer 1

Assuming all Al will be consumed in the reaction.

From the given equation, 2 mole of Al produce 2 mole of
`Na_3AlO_3`.

So, 1 mole of Al produce 1 mole of
`Na_3AlO_3`. .....statement 1)

Number of moles of Al in 258 gram of Al.

`n = (mass)/(molar\ mass)\\\\n = (258)/(27)\ moles\\\\n = 9.556 \ moles`

Therefore, from statement 1) number of moles of
`Na_3AlO_3` produced is also 9.556 moles.