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Find the conjugate and product of the following surds


2i + 9

User Fred Hors
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1 Answer

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Answer:

The conjugate of 2i + 9 = -2i + 9

Product of (2i+9) and (2i+9) is 36i + 77

Explanation:

Given - 2i + 9

To find - Find the conjugate and product of the following surds

Proof -

We know that,

The sum and difference of two simple quadratic surds are said to be conjugate surds to each other.

To find a complex conjugate, simply change the sign of the imaginary part (the part with the i ).

So,

The conjugate of 2i + 9 = -2i + 9

Now,

Product of surd (2i+9) is

(2i+9)(2i+9) = 2i(2i) + 2i(9) + 9(2i) + 9(9)

= 4i² + 18i + 18i + 81

= -4 + 36i + 81 { because i² = -1 }

= 77 + 36i

⇒Product of (2i+9) and (2i+9) is 36i + 77

User Chsh
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