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A and b are positive integers and a-b=2. Evaluate the following:

(27^1/3b)/ ( 9^1/2a)

(this is urgent)

User Signe
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1 Answer

2 votes
Answer:
a) 1/27
b) 1
c) 125
Explanation:
a) (9^(0.5b))/(3^a)
(3²)^(0.5b) ÷ (3^a)
(3^b) ÷ (3^a)
3^(b - a)
a - b = 3
b - a = -3
3^(-3)
1/27
b) (27^(1/3b)) /(9^(0.5b))
(3³)^(b/3) ÷ (3²)^(0.5b)
(3^b) ÷ (3^b)
1
c) ( 125^(1/3a))/(25^(1/2b))
(5³)^(a/3) ÷ (5²)^(b/2)
5^a ÷ 5^b
5^(a - b)

125
User Sswierczek
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