Question

10000 J of heat energy is absorbed per cycle by a diesel engine that is 11% efficient. How much energy does it expel to the environment per cycle? (J)

Answer 1

8900 J

Step-by-step explanation:

Let heat absorbed be Q1 and heat rejected be Q2.

Q1 = 1000 J, efficiency η = 11% = 0.11

Then, Efficiency of engine can be found be using the following formula,

`\eta = (Q_1-Q_2)/(Q_1)`

⇒
`0.11 = (10000-Q_2)/(10000)\\Q_2 = 10000- 1100= 8900 J`

Therefore, energy does it expels to the environment per cycle = 8900 J

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