Answer:
–99 °C
Step-by-step explanation:
From the question given above, the following data were obtained:
Initial pressure (P₁) = 1.5 atm
Initial temperature (T₁) = 25 °C
Final pressure (P₂) = 1 atm
Change in temperature (ΔT) =?
Next, we shall determine the final temperature. This can be obtained as follow:
Initial pressure (P₁) = 1.5 atm
Initial temperature (T₁) = 25 °C + 273 = 298 K
Final pressure (P₂) = 1 atm
Final temperature (T₂) =?
P₁/T₁ = P₂/T₂
1.5 / 298 = 1 / T₂
Cross multiply
1.5 × T₂ = 298
Divide both side by 1.5
T₂ = 298 / 1.5
T₂ = 199 K
Converting 199 K to °C, we have:
T(°C) = T(K) – 273
T₂ = 199 – 173
T₂ = –74 °C
Finally, we shall determine change in temperature. This can be obtained:
Initial temperature (T₁) = 25 °C
Final temperature (T₂) = –74 °C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = –74 – 25
ΔT = –99 °C
Thus, the change in the temperature is –99 °C