Question

Given the arithmetic series:2+4+6....Find the sum of 41st term to 47th term
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Answer 1

Explanation:

To find the 41st term to 47th term, we must find the equation of how to get those terms.

The equation for arithmetic terms is
`a_(n) =a_(1) + (n-1)d`, where d is the difference between two side-by-side terms.

By using this equation format, we get the equation
`a_(n) =2+ (n-1)2 = 2n`

That means the terms are

`a_(41) =2*41 = 82\\a_(42)=2*42 = 84\\a_(43) = 2*43 = 86\\a_(44) = 2*44 = 88\\a_(45) = 2*45 = 90\\a_(46)=2*46 = 92\\a_(47) = 2*47 = 94\\`

Now to find the sum, we just add all the terms up simply

Sum = 82 + 84 +86 + 88 + 90 + 92 +94 = 616

Hope that helps!