Answer:
(a) AC = 12.565 m
(b) bearing of C from A is 90°
(c) BT = 9.373 m
Explanation:
(a) extend North line down & perpendicular to AC.
Call that perpendicular intersection "P".
∠BAC = 90° - 53° = 37°
cos 37° = AP/15
0.7986 = AP/15
AP = 11.979 m
∠PNC = 180° - 161° = 19°
∠BCP = 90° - 19° = 71°
18 cm = 0.18 m (red flag note: 18 cm looks very out of scale for the picture)
cos 71° = CP/0.18
0.3256 = CP/0.18
CP = 0.586 m
AC = 11.979 + 0.586 = 12.565 m
(b) The bearing to C from A is 90°
(c) tan 58° = 15/x
1.6003 = 15/x
x = 9.373 m