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A student titrated 50 cm of sulphuric acid (H2SO4)of an unknown concentration in a flask with sodium hydroxide (NaOH). The acid required 30 cm3 of 0.500 mol/dm3 NaOH to reach the end point H2SO4(aq) +
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A student titrated 50 cm of sulphuric acid (H2SO4)of an unknown concentration

in a flask with sodium hydroxide (NaOH).
The acid required 30 cm3 of 0.500 mol/dm3 NaOH to reach the end point
H2SO4(aq)
+ 2NaOH(aq)
Na2SO4(aq) + 2H2O()
Calculate the concentration the acid.
Concentration =
mol/dm3​

User Chris Bedford
by
8.2k points

1 Answer

7 votes
No. of mol. of NaOH used: (30/1000)*0.5= 0.015mol
Mole ratio of NaOH:H2SO4= 2:1
No. of mol. of H2SO4: 0.015/2= 0.0075mol
Conc. of acid= 0.0075/(50/1000)= 0.15moldm^-3

Hope it helps, drop a thanks
User Eduard Dumitru
by
8.6k points
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