Answer:
The equation of the the line that is perpendicular to 4·x + 6·y = 1 and that has a greater intercept to the line 2·x + 3·y = 18 can be 2·y - 3·x = 14
Explanation:
The line which is perpendicular to the required line = 4·x + 6·y = 1
The line with which the required line has a greater intercept = 2·x + 3·y = 18
Solution;
The relationship between the slope, m₁, of a straight line, y = m₁·x + c₁ perpendicular to another straight line, y = m₂·x + c₂, with slope m₂ is given as follows;
m₁ = -1/m₂
Rewriting the equation of the given line in slope and intercept form gives;
4·x + 6·y = 1
6·y = 1 - 4·x
y = 1/6 - 4·x/6 = 1/6 - 2·x/3 = 1/6 - (2/3)·x
∴ y = 1/6 - (2/3)·x
Therefore, the slope, 'm₁', of the line y = 1/6 - (2/3)·x, is m₁ = -(2/3)
The slope of the perpendicular line, is therefore, m₁ = -1/m₂
∴ m₂ = -1/m₁
m₂ = -1/(-(2/3)) = 3/2
The intercept of a straight line of the form y = m·x + c is 'c'
The intercept of the line 2·x + 3·y = 18 is obtained by rewriting the equation of the line in slope and intercept form as follows;
2·x + 3·y = 18
y = 18/3 - (2/3)·x = 6 - (2/3)·x
y = 6 - (2/3)·x = -(2/3)·x + 6
y = -(2/3)·x + 6
By comparing the above equation to the equation, y = m·x + c, we have;
c = 6
The intercept of the line y = -(2/3)·x + 6, which is the same line as 2·x + 3·y = 18 is 6
∴ The intercept of the required line, c₂ > 6
The equation of the required line in slope and intercept form, y = m·x + c, can therefore be;
y = (3/2)·x + 7
By multiplying by 2, we get;
2·y = 3·x + 14
∴ The equation of the line can be 2·y - 3·x = 14.